Diketahui: tan x = p Tentukan: a. Sin (90°+x)=... b. Cos (180°-x)=...

tan x = p
tan x  = y/x
x=1, y = p, r = √(x²+y²) = √(p²+1)

sin x = y/r = p/√(p²+1)
cos x = x/r = 1/√(p²+1)

a. sin (90- x)=  cos x = 1/√(p²+1)
b. cos (180 - x)= - cos x = - 1/√(p²+1)

tan x = p
sin x / cos x = p

a. sin (90° + x) = cos x
cos x = sin x /p
sin (90° + x) = sinx /p

b. coa (180°-x) = - cos x
-cos x = -sin x /p
cos (180°-x) = - sinx/p