ini caranya gimana yg gak tau/ragu jangan jawab yh..

y = - sin (2x + π/2)
dy/dx = y' = - 2 cos (2x + π/2)

dy/dx + 2y
= -2 cos (2x + π/2) + 2(- sin (2x + π/2))
= -2 cos (2x + π/2) - 2 sin (2x + π/2) =====> x = π/2
= -2 cos (2(π/2) + π/2) - 2 sin (2(π/2) + π/2)
= -2 cos 3π/2 - 2 sin 3π/2 =======> 3π/2 = 270°
= -2 (0) - 2 (-1)
= 0 + 2
= 2