Matematika

Pertanyaan

diketahui sin α = √7/4. jika α berada di kuadran II,maka nilai cos α = ..

2 Jawaban

  • Mapel : Matematika
    Kelas : X SMA
    Bab : Trigonometri

    Pembahasan :
    Sin A = (√7)/4

    Depan = √7
    Miring = 4
    Samping = - 3 (Pythagoras)

    Maka....
    Cos A = Samping/Miring
    Cos A = -3/4
  • sin a = [tex] \frac{depan}{miring} [/tex]
    sin a =[tex]\frac{ \sqrt{7} }{4} [/tex]
    depan = [tex] \sqrt{7} [/tex]
    miring = 4

    [tex] samping^{2} [/tex] = [tex]miring ^{2} - depan^{2} [/tex]
    [tex] samping^{2} [/tex] = [tex]4^{2} - \sqrt{7}^{2} [/tex]
    [tex] samping^{2} [/tex] = 16 - 7
    [tex] samping^{2} [/tex] = 9
    samping = [tex] \sqrt{9} [/tex]
    samping = 3

    cos a = [tex] \frac{samping}{miring} [/tex]
    cos a = [tex] \frac{3}{4} [/tex]
    karena di kuadran II, maka :
    cos a = -[tex] \frac{3}{4} [/tex]




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