Matematika

Pertanyaan

Nilai= Sin 30° +cos²45° + tan²60° per cosec 30°cotan 45

2 Jawaban

  • Mapel : Matematika
    Kelas : X SMA
    Bab : Trigonometri

    Pembahasan :
    (Sin 30° + Cos² 45° + Tan² 60°)/(Cosec 30° Cotan 45°)
    = (1/2 + 1/2 + 3)/(2 . 1)
    = 4/2
    = 2
  • [sin 30° + cos^2 45° + tan^2 60°]/
    [cosec 30° cotan 45°]
    = [1/2 + (1/2 akar 2)^2 + (akar 3)^2]/
    [2 × 1]
    = [1/2 + (1/4 × 2) + 3]/2
    = (1/2 + 2/4 + 3)/2
    = (1/2 + 1/2 + 3)/2
    = (1/2 + 1/2 + 6/2)/2
    = (8/2)/2
    = 4/2
    = 2

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