f(x)=2ax+3b Jika f(2)=0 ; f(3)=1 2b-3a=?
Matematika
pramestimeydi
Pertanyaan
f(x)=2ax+3b
Jika
f(2)=0 ; f(3)=1
2b-3a=?
Jika
f(2)=0 ; f(3)=1
2b-3a=?
1 Jawaban
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1. Jawaban mabuchi
F(x)=2ax+3b
Jika
f(2)=0 ; f(3)=1
2b-3a=?
f(2)=0
2ax+3b =0
4a+3b = 0
f(3)=1
2ax+3b = 1
6a+3b =1
4a+3b=0
6a+3b=1
ㅡㅡㅡㅡㅡ (-)
-2a=-1
a= 1/2
4a+3b=0
2+3b= 0
3b=-2
b= - 2/3
2b - 3a=?
2(1/2) - 3(-2/3
2+2 =4