mohon bantu lgi kakak :)

t ∆= √10²-6²=√100-36=√64=8 cm
L ∆ = ½×a×t=½×12×8= 48 cm²
L trapesium = ½(a+b)t=½(38+12)10=250 cm²
L ABCDE= L ∆+L trapesium =48 cm²+250 cm²=298 cm² (A)

L.trapesium = (38+12)×10÷2= 250 cm2
L.segi3 = 12×8÷2 = 48 cm2

L.ABCDE = 298 cm2
"""A"""