pada segitiga ABC,sudutA=45derajat,AB=6cm dan BC=6akar2 maka sudutb =

Aturan sinus

ΔABC, <A = 45, AB = 6 , BC = 6√2

AB/sin C = BC /sin A
sin C = AB. sin A / BC
sin C = 6 . sin 45 / 6 √2
sin C = ( 6. 1/2 √2 ) / (6√2)
sin C = 1/2 = sin 30
<C = 30

<B = 180 - A - C
<B= 180 - 45- 30
<B = 105°