diketahui f(x) = 2ax + (a-1). jika f(1) = 3, maka nilai a adalah....

f(x) = 2ax + (a - 1)
f(1) = 3
2a(1) + (a - 1) = 3
2a + (a - 1) = 3
3a - 1 = 3
3a = 3 + 1
3a = 4
a = 4/3

f(1)= 3
f(x) = 2ax + (a-1)
3 = 2a(1) + (a-1)
3. = 2a + a-1
3 = 3a-1
3+1 = 3a
4. = 3a
a = 4/3

jadi a = 4/3

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