Dinyatakan oleh f(x)=x+2 dan (gof)(x)=2x^2+4x+1 maka g(2)=

f^-1(x) = x-2
g(x). = (gofof^-1) = 2(x-2)²+4(x-2)+1
=2(x²-4x+4)+(4x-8)+1
=2x²-8x+8+4x-8+1
=2x²-4x+1

g(2)=(2×2²)-(4×2)+1 = 8-8+1 = 1

2x^2+4x+1 = g(x+2)

g(x+2)
y=x+2
x=2-y diubah lambangnya jd 2-x
masukan ke g°f

2(2-x)^2+4(2-x)+1=
2(4-4x+x^2) +8-4x+1
g(x)= 2x^2-12x+17
g(2)= 2.2^2+17= 1