bantuin nomor 9 pakai cara yaaa terima kasih

Trigonometri
<A lancip,, <B tumpul
tan A = 5/12 --> tan A = y/x
triple pitagoras --> x,y, r = 12, 5, 13
sin A = y/r  = 5/13
cot A = x/y = 12/5

cos B = 4/3 --> cot B = x/y
triple pitagoras --> x,y, r = 4,3, 5
sin B = - y/r = - 3/5
cos B = - x/r = - 4/5
sec B = 1/cos B = - 5/4

(cot A . sec B)/(sin A sin B) =
= [ (12/5)(-5/4) ] / [(5/13)(-3/5)]
= (-3)/(-3/13)
= 13

(cot A . sec B)/(sin A sin B) =
= [ (12/5)(-5/4) ] / [(5/13)(-3/5)]
= 13