diketahui fungsi f(x) = x+1/x-3, x = 3 dan g(x) = x²+x+1. Tentukan nilai komposisi fungsi dari (gof)(2) !

f(x) = [tex] \frac{x+1}{x-3} [/tex] dan g(x) = x²+x+1
(gof)(x) = g([tex] \frac{x+1}{x-3} [/tex] = [tex] (\frac{x+1}{x-3} )^{2} [/tex] +[tex] \frac{x+1}{x-3} [/tex] + 1
(gof)(2) = 9 + (-3) + 1 = 7