Jika f(x)=((1-x)(x+1))/x,maka f^' (x)adalah

f(x) = (1-x)(x+1)/x
f(x) = (x+1-x²-x)/x
f(x)= 1-x²/x
misalkan
u= 1-x²
u'= -2x
v= x
v'= 1

f(x)= u/v
f'(x) = u'v-uv'/v²
=-2x(x) - 1-x²(1)/v²
=-2x²-1-x²/(x)²
=-x²- 1/x²
=-(x²+1)/x²

semoga membantu

turunan

f(x) = (1-x)(x+1)  /(x)
f(x)= (1- x²) / (x)
f(x) = ( 1 - x²)(x⁻¹)
f(x) = x⁻¹ - x

f'(x)= -1 x⁻² - 1
f ' (x) = - 1/x²  - 1
atau
f' (x) = (-1 - x²) /x²
atau
f'(x) = -(x²+1)/(x²)