Tolong dibantu ya sekalian caranyaa

f(x,y) = 5(x+y)

2x + y= 6
A -->  x = 0, y =6
B --> y =0 , x = 3

x+ 3y = 6
C--> x= 0 , y = 2
D -->y = 0 , x= 6

titk potong
2x + y = 6
x+ 3y = 6....kalikan 2
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2x + y = 6
2x + 6y = 12
kurangkan -5y = - 6
y = 6/5

x + 3y = 6
x = 6 - 3y
x = 6 - 3(6/5)
x = 12/5
E (12/5  , 6/5)

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titik pojok yng memnuhi peertidaksamaan
(3,0) --->f(x,y) = 5(3+0)= 15
(6,0) ---> f(x,y) = 5(6+0) = 30
(12/5 , 6/5) -> f(x,y)  = 5(12/5 +6/5) = 18
nilaimaksimum= 30