titik A (6,4,-2) titik B (2,-4,2) titik C (14,2p,-10) segaris untuk nilai P

AB
= B - A
= (-4,-8,4)

BC
= C - B
= (10,2p + 4,-12)

segaris, maka
AB = k.BC
(-4,-8,4) = k(12,2p + 4,-12)

12k = -4
k = -1/3

-1/3 (2p + 4) = -8
-2p - 4 = -24
-2p = -20
p = 10