Jika jari jari 10 cm dan sudut pusat AOB 120° tentukan panjang busur AB dan luas juring AOB

luas= 120°/360°.π.r²
=⅓.3,14.10.10
=⅓.314
=104.6 cm²
panjang busur=keliling
=⅓.2.π.r
=⅓.2.3,14.10
=⅓.62,8
=20,93 cm

r = 10 cm
< AOB / SUDUT PUSAT = 120°
JADI ,
=> Panjang Busur = ( <Pusat ÷ 360° ) × 2πr
= ( 120° ÷ 360° ) × 2×3,14×10
= 1 / 3 × 62,8
= 20,93 cm
= 21 cm
=> Luas Juring = ( < Pusat ÷ 360° ) × πr²
= ( 120° ÷ 360° ) × 3,14 × 10²
= 1 / 3 × 314
= 104,66 cm²
= 105 cm²
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