1. Larutan asam asetat 0,1 M sebanyak 20 mL (Ka = 10-5) dititrasikan oleh larutan NaOH 0,1 M . Pada saat penetesan NaOH mencapai 15 mL , pH larutan adalah.....

n CH3COOH = 2 mmol
n NaOH = 1,5 mmol

CH3COOH + NaOH --->>> CH3COONa + H2O
2................1,5.................
1,5.............1,5....................1,5.................1,5
0,5..............-........................1,5...............1,5

H+ = Ka na/ng
= 10^-5 0,5/1,5
= 3,3.10^-6 M

pH = 6 -log 3,3
= 6 - 0,5
= 5,5
jawaban D