Jika f(×)=3×+1 dan g(×)=×pangkat2+1,maka nilai (f•g)(-2) adalah

f(x) = 3x + 1
g(x) = x² + 1

(fog)(-2)
= f(g(-2))
= f((-2)² + 1)
= f(4 + 1)
= f(5)
= 3(5) + 1
= 15 + 1
= 16

f(×)=3×+1
g(×)=x²+1,maka nilai (f•g)(-2)
Fog(x) = 3(x²+1) + 1
Fog(x) = 3x² + 4
Fog(-2) = 3(-2)² + 4
= 16