pada segitiga ABC,jika diketahui a=8 cm,b=4√2 cm,dan

SEGITIGA ABC
a = 8 cm
b = (4 akar 2) cm
< A = 45°

.....a...............b
----------- = ---------
sin <A........sin <B

......8................4 akar 2
------------ = -------------------
sin 45°..............sin <B

......8................4 akar 2
-------------- = ---------------
1/2 akar 2...........sin <B

(4 akar 2)(1/2 akar 2) = 8 × sin <B
4 = 8 × sin < B
sin <B = 4/8
sin < B = 1/2
<B = arc sin 1/2
<B = 30°
Jadi sudut B adalah 30°