Jika y=3/4(3x-1)(x+2) maka dy/dx=...

misal
u =3 , maka u' = 0
v = 4 (3x-1)(x+2)
v= 4 (3x^2+6x-x-2) = 4(3x^2+5x-2)
= 12 x^2+20x -8 maka v' = 24x+20

dy/ dx= (u'v - uv')/v^2
=(0.( 12 x^2+20x -8) - 3 (24x+20))/ (24x+20)^2
= (0- 72x-60)/ (24x+20)^2
= -72 x-60 / (24x+20)(24x+20)
=(24x +20) -3/ (24x+20)(24x+20)
= -3/ (24x+20)