Matematika

Pertanyaan

Jika 16x^2 - 49y^2=333 dan 4x-7y=9 maka

1 Jawaban

  • 16x^2 - 49y^2 = 333
    (4x + 7y)(4x - 7y) = 333
    (4x + 7y)(9) = 333
    4x + 7y = 333/9
    4x + 7y = 37

    4x + 7y = 37
    4x - 7y = 9
    ----------------- +
    8x = 46
    x = 46/8 = 23/4

    4x + 7y = 37
    4x - 7y = 9
    ------------------ --
    14y = 28
    y = 2

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