Fungsi g(x) = x + 3 dan (fog)(x) = { x }^{ 2 }+11x+20x ​2 ​​ +11x+20. maka f(x + 1)

fungsi komposisi
fog(x) = x² + 11x + 20
g(x)= x+ 3

fog(x) = f{g(x)} = f(x+3)
f(x+3)= fog(x)
f(x+3) = x² +11x + 20
f(x) = (x -3)² + 11(x -3) + 20
f(x+1) = (x +1 -3)² + 11(x +1-3) + 20
f(x+1) = (x-2)² + 11(x -2)+ 20
f(x+1) = x² - 4x + 4 + 11x -22 + 20
f(x+1) = x² + 7x + 2