hitunglah konsentrasi ion H+ dakam 250ml larutan yang mengandung 0,01 mol sr(oH)oH2

M = n / v
M = 0.01 / 0.25 = 0.04 M
OH- = v. basa x Ma
OH- = 1 x 0.04 = 0.04 M

H+ = Kw / OH-
H+ = 10^-14 / 4 x 10^-2
H+ = 1/4 x 10^-12
H+ = 0.25 x 10^-12
H+ = 2.5 x 10^-13