suatu barisan aritmatika diketahui suku ke 6 adlh 42 dan suku ke 14 qdlh 66 maka nilai u2+u10 adlh

U14= a+13b =66
U6= a+5b =42
----------------------- -
---------) 8b= 24 / b = 3
b=3 subtitusi ke a+5b=42
a+5(3)=42
a+15=42
a=27

U2= a+b= 27+3=30
U10= a+9b= 27+9(3) = 54

U2+U10=30+54=84
Follow my INSTAGRAM : alhamdirojil

a + 5b   = 42
a + 13b = 66
----------------- -
      -8b = -24
         b = 3

a + 5b = 42
a + 15 = 42
a = 27

U2 = 27 + (2-1) 3
      = 27 + 3
      = 30

U10 = 27 + (10-1) 3
        = 27 + 27
        = 54


Maka,

U2 + U10
= 30 + 54
= 84


Semoga Membantu!!!