Matematika

Pertanyaan

Diketahui proyeksi scalar ortogonal a= (
8 -2 4) pada b= (
m 0 4) adalah 8 , panjang a+ 2b adalah

1 Jawaban

  • diketahui
    a = (8, -2, 4)
    b = (m, 0, 4)

    a.b = (x1.x2) + (y1.y2) + (z1.z2)
    a.b = (8.m) + (-2.0) + (4.4)
    a.b = 8m + 16

    |b| = √x2² + y2² + z2²
    |b| = √m² + 16

    proyeksi scalar = a.b/|b|
    8 = 8m + 16/|b|
    8|b| = 8m + 16
    |b| = 8m + 16/8
    |b| = m + 2

    √m² +16 = m + 2
    m² + 16 = (m + 2)²
    m² + 16 = m² + 4m + 4
    m² - m² = 4m + 4 - 16
    0 = 4m -12
    12 = 4m
    m = 3

    a = (8, -2, 4)
    2b = 2(3, 0, 4)
    2b = (6, 0, 8)
    a + 2b = (8, -2, 4) + (6, 0, 8)
    a + 2b = (14, -2, 12)
    |a + 2b| = √14² + (-2)² + 12²
    |a + 2b| = √196 + 4 + 144
    |a + 2b| = √344
    |a + 2b| = 2√86

    Semoga dapat membantu
    Maaf kalo salah

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