jika f^1 (4×+5)=8× +12,maka f(x)

fungsi invers

f⁻¹(4x + 5) = 8x + 12
f( 8x +12) = 4x + 5
8x + 12 = y
8x = y- 12
x = (y-12) /8

f(x) = 4 (x-12)/8  + 5
f(x) = 1/2(x -12) + 5
f(x)= 1/2 x - 6 + 5
f(x)= 1/2 x - 1