sebanyak 10 ml larutan asam asetat (ka= 10-5) dengan ph =5 dicampur dgn 90 ml air ph larutan mrnjafi?

H⁺ = √Ka . M
10⁻⁵ = √10⁻⁵ . M
M = 10⁻⁵

10 . 10⁻⁵ = M . 100
M = 10⁻⁶

H⁺ = √Ka . M
H⁺ = √10⁻⁵ . 10⁻⁶
H⁺ = 10^(-11/2)
pH = 11/2
pH = 5.5 ⇒ Jawab