Jika diketahui harga pH larutan NH3 0,001 M sebesar 10, maka harga pH dari larutan NH4Cl 0,1 M yaitu...

pOH = pKw - pH
pOH = 14 - 10
pOH = 4

pOH = - log OH-
OH- = 10^-4

OH- = √ kb x Mb
10^-4 = √ kb x 0.001
10^-8 = kb x 10^-3
kb = 10^-5

H+ = √ kw / kb x Mg
H+ = √ 10^-14 / 10^-5 x 10^-1
H+ = √ 10^-10
H+ = 10^-5

pH = - log H+
pH = 5