Kimia

Pertanyaan

Sebanyak 2,05 gr CH3COONa (Mr = 82) dilarutkan dalam air samlai volume 100 mL, pH larutan yaitu... (Ka CH3COOH = 10^-5)

1 Jawaban

  • m CH3COONa : 2,05 gr
    Mr CH3COONa : 82
    Volum larutan : 100 mL=0.1 L
    ka CH3COOH : 10^-5

    mol CH3COONa
    =m/Mr
    =2,05/82
    =0,025
    Molaritas CH3COONa
    = n/V
    = 0,025/0,1
    = 0,25

    (OH-)
    =√kw/ka x M
    =√10^-14/10^-5 x 25.10^-2
    =√10^-11.25
    =10^-5,5 x 25

    POH
    =-log10^-5,5 x 25
    =5,5-log25

    PH
    =14-(5,5-log25)
    =8,5+log25
    =

Pertanyaan Lainnya