Sebanyak 2,05 gr CH3COONa (Mr = 82) dilarutkan dalam air samlai volume 100 mL, pH larutan yaitu... (Ka CH3COOH = 10^-5)
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Pertanyaan
Sebanyak 2,05 gr CH3COONa (Mr = 82) dilarutkan dalam air samlai volume 100 mL, pH larutan yaitu... (Ka CH3COOH = 10^-5)
1 Jawaban
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1. Jawaban Dea2311111
m CH3COONa : 2,05 gr
Mr CH3COONa : 82
Volum larutan : 100 mL=0.1 L
ka CH3COOH : 10^-5
mol CH3COONa
=m/Mr
=2,05/82
=0,025
Molaritas CH3COONa
= n/V
= 0,025/0,1
= 0,25
(OH-)
=âkw/ka x M
=â10^-14/10^-5 x 25.10^-2
=â10^-11.25
=10^-5,5 x 25
POH
=-log10^-5,5 x 25
=5,5-log25
PH
=14-(5,5-log25)
=8,5+log25
=