jika c(n-3.2)=36, maka nilai yang memenuhi adalaj

(n-3)! / 2!(n - 3 - 2)! = 36
(n-3).(n-4).(n-5)! / 2×1(n - 5)! = 36
(n - 3)(n - 4) = 36 × 2
n² - 7n + 12 = 72
n² - 7n + 12 - 72 = 0
n² - 7n - 60 = 0
(n - 12)(n + 5) = 0
n = 12 atau n = -5