pH larutan Mg(OH)^2 0.3 M adalah...? (Diketahui Kb = 3 x 10^-5) Jgn lupa caranya ya... :D Thx
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bluediamond1080
Pertanyaan
pH larutan Mg(OH)^2 0.3 M adalah...?
(Diketahui Kb = 3 x 10^-5)
Jgn lupa caranya ya... :D
Thx
(Diketahui Kb = 3 x 10^-5)
Jgn lupa caranya ya... :D
Thx
1 Jawaban
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1. Jawaban AC88
OH⁻ = vKb . M
OH- = v3 . 10^-5 . 0.3
pOH = 3 - log 3
pH = 11 + log 3
pH = 11.477 ⇒ Jawab