alas sebuah prisma berbentuk persegi panjang . perbandingan panjang,lebar dan tinggi 2:3:5 jika volume prisma 1920 cm2 . tentukan luas prisma

2x×3x×5x=1920
30x pangkat3=1920
x pangkat3=1920÷30
x pangkat3=64
x=3_/64
x=4 cm
2x=2×4=8 cm
3x=3×4=12 cm
5x=5×4=20 cm
Lp prisma=Lp balok
=2 (8×12+8×20+12×20)
=2 (96+160+240)
=2×496
=992 cm2

p : l : t = 5 : 3 : 2

v = 1920 cm^3

v = p x l × t
1920 = 5x × 3x × 2x
1920 = 30x^3
x^3 = 1920/30
x^3 = 64
x^3 = 4^3
x = 4

p = 5x = 5×4 = 20
l = 3x = 3×4 = 12
t = 2x = 2× 4 = 8

L = 2pl + 2pt + 2lt
= 2×20×12 + 2×20×8 + 2×12×8
= 480 + 320 + 192
= 992 cm^2