Diketahui segitiga ABC sudut A=60° sudut B=75° panjang BC=6cm maka, panjang AB=.......cm

<C = 180 - <A - <B
<C = 180 - 60 - 75
<C = 45
AB/sin C = BC/sin A
AB/sin 45 = 6/sin 60
AB/(√2/2) = 6/(√3/2)
AB = 6 × √2/2 × 2/√3
AB = 6√2/√3
AB = 6√2/√3 × √3/√3
AB = 6√6/3
AB = 2√6