Tolong dibantu skarang di buat jlanny ?? mksih

Nomor 25
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Diket :
n = 10 mol
Perubahan suhu, delta T = 700 - 400 = 300 K
Kapasitas kalor dlm keadaan Isobarik (P = tetap), Cp = 20,8 J/mol. K

Tanya :
Kalor, Q = ___?

Jawab :
Q = delta U + W
Q = 3/2.n.R.delta T + n.R.delta T
Q = 5/2.n.R.delta T
Q = 5/2•10•8,31•300
Q = 62325
Q = 6,2325 x 10^4 J

Jawaban : tdk ada di pilihan

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