Mohon dibantu gan buat remed soalnye :3

1a) CaCO3
Biloks Ca + biloks C + 3 biloks O = 0
+2 + biloks C + 3(-2) = 0
Biloks C = +6-2 = +4

1b) K2C2O4 (sy ganti yg mungkin ya)
2 biloks K + 2 biloks C + 4 biloks O = 0
2(+1) + 2 biloks C + 4(-2) = 0
2 biloks C = +6
Biloks C = +3


2a) 2 mol CH3COOH = 2(2.12+4.1+2.16) = 2(60) = 120 gram
2b) 4 mol CO2 = 4(12+2.16) = 4(44) = 176 gram

3) sy ambil pd keadaan STP ( 1 mol = 22,4 liter)
a) 0,6 mol CH4 = 0,6×22,4 = 13,44 liter
b) 2,5 mol NH3 = 2,5×22,4 = 56 liter