Nilai f '(3) untuk fungsi f(x) = (x + 4)(x2 - 5) adalah ….

f(x) = (x + 4)(x² - 5)
f(x) = x³ - 5x + 4x² - 20
f'(x) = 3x² + 8x - 5
f'(3) = 3(3)² + 8(3) - 5
f'(3) = 3(9) + 8(3) - 5
f'(3) = 27 + 24 - 5
f'(3) = 46

f(x)=(x+4)(x²-5)=x³-5x+4x²-20=x³+4x²-5x-20
f'(x)=3x²+8x-5
f'(3)=3.3²+8.3-5=3.9+24-5=27+24-5=46