Tentukan periode fungsi trigonometri berikut a. y = sin 3x b. y = 3 cos 1/2x

Y = a sin (bx + c) --> periode = 2π/b = 360/b
y = a cos (bx + c) --> periode = 2π/b  =360/b

1) y = sin 3x
a = 1,  b = 3 , c = 0
P = 2π/b = 2π/3 = 120°

2) y = 3 cos 1/2 x
a = 3
b = 1/2
c = 0

p = 2π/b = 2π/(1/2) = 4π = 4(180) = 720°